I when put all my calculation in one formula,get this.
I added distance (d)=from feet to sailor C.G. now we can play with hook height(L) as well.
As you can see sail angle (C) dont exist in formula,because Fsail dont change when sail angle change.
If harness line is 100% horizontal then B=0,but if you use angle below horizontal than you must have minus sign to formula works correct,
anyway, this is never case in reality because harness line allways stay slightly upright...
If sailor stay at 100% upright,then A=90, cos90=0 ,as you know multiplication by zero gives zero, so Fsail =0 ,what is also correct becuase if sailor stay 100% upright his pull is zero so Fsail is zero too....
get picture,take protractor to messure angle A and B,from board width you know what is (X),(h) is ussualy about 40% of mast and you can find Fsail..for this picutre and this numbers I get Fsail=33kg
below explanation why sail angle(C) dont change Fsail..